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Given that tanθ = 1/√3, find the value of (〖cosec〗^2 θ-〖sec〗^2 θ)/(〖cosec〗^2 θ+〖sec〗^2 θ)
Given that tanθ = 1/√3, find the value of (〖cosec〗^2 θ-〖sec〗^2 θ)/(〖cosec〗^2 θ+〖sec〗^2 θ)
BerdiOre
March 03, 2019
Given that tanθ = 1/√3 find the value of (〖cosec〗^2 θ-〖sec〗^2 θ)/(〖cosec〗^2 θ+〖sec〗^2 θ),
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