Here's a quick overview:
1. write out the average mass as a sum of the isotope, multiplied by its % abundance (x):
average = (isotope1)(x) + (isotope2)(1-x)
(the % abundances MUST add up to 1, which is why we can use only one variable, x, and simply write 1-x for the second isotope.)
2. solve for x
3. put x back into the original equation - if it yields the given average mass, it's correct! If not, something's off
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Problem Text:
Silver exists in two stable forms: 107Ag (106.90 amu) and 109Ag (108.90 amu). If the average atomic mass of Ag is 107.87 amu, what is the % abundance of 107Ag?
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